3[x-2(x-5)]-2=-3x+29

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Solution for 3[x-2(x-5)]-2=-3x+29 equation:


Simplifying
3[x + -2(x + -5)] + -2 = -3x + 29

Reorder the terms:
3[x + -2(-5 + x)] + -2 = -3x + 29
3[x + (-5 * -2 + x * -2)] + -2 = -3x + 29
3[x + (10 + -2x)] + -2 = -3x + 29

Reorder the terms:
3[10 + x + -2x] + -2 = -3x + 29

Combine like terms: x + -2x = -1x
3[10 + -1x] + -2 = -3x + 29
[10 * 3 + -1x * 3] + -2 = -3x + 29
[30 + -3x] + -2 = -3x + 29

Reorder the terms:
30 + -2 + -3x = -3x + 29

Combine like terms: 30 + -2 = 28
28 + -3x = -3x + 29

Reorder the terms:
28 + -3x = 29 + -3x

Add '3x' to each side of the equation.
28 + -3x + 3x = 29 + -3x + 3x

Combine like terms: -3x + 3x = 0
28 + 0 = 29 + -3x + 3x
28 = 29 + -3x + 3x

Combine like terms: -3x + 3x = 0
28 = 29 + 0
28 = 29

Solving
28 = 29

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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